Question

Convert Rectangular points into Polar points:

(4,0)

When converting I got (4,0) using the methods of.

sqrt(x^2+y^2)

sqrt(4^2+0^2)

sqrt(4^2)=4

x=4

y=tan^-1(y/x)

tan^-1(0/4)=0
Where do I go from here?

Answer 1

And we know that the tangent of 0 is 0 so that is is

Your polar coordinate will be (4,0^\circ)\]

Answer 2

Ahh wrote that bad...

\[\large (4,0^\circ)\]

Answer 3

Ah I recognize you p:

Well thank you again!

Answer 4

lol of course! :P

Answer 5

Really quick question

I also have to transform (0,3)

and I got (3,0deg)

is that right?

@johnweldon1993

Answer 6

If it's weird to think of a 0 degree...just remember

A "polar coordinate" is a point, broken into a radius and an angle from the positive 'x-axis'...for example let's take a random point (5,4)



So if you have a point (4,0)



As you can see, we are already ON the x-axis so there is no angle to make!

Answer 7

Hmm...

(0,3)

Tell me, what is \(\large \tan^{-1}(\frac{3}{0})\)

Answer 8

Dividing by 0

Tricky huh?

Now obviously this has "imaginary numbers" written all over it

BUT!!!! We can look at it graphically as I have posted above

Answer 9

My calculator says

(tan^-1(0/3)=0

Answer 10

Right (0/3) is indeed 0

But the point you have provided is (0,3) which would lead to \(\large \tan^{-1}(\frac{3}{0})\)

Answer 11

Because remember it is

\[\large \theta = \tan^{-1}(\frac{y}{x})\]

Answer 12

Opp. :( silly mistakes will be the end of me!

Answer 13

Lol well remember the original slope "rise over run"

rise = vertical = y
run = horizontal = x

:)

Answer 14

Now I'm still confused because I'm getting 0 still.

Answer 15

Or of course, graph it out to make sure you can at least see why



Now you are SOLVING for \(\large \theta\) using tangent which you know is opposite/adjacent so y/x !

Answer 16

And your calculator might just be "erroring" out

We know very well that anything divided by 0 is "indeterminant" right?