Find the height, in feet, of the rock after 5 seconds in the air. A rock is launched from a cannon. It’s height, h(x), can be represented by a quadratic function in terms of time, x, in seconds. After 1 second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air.
@JoKeR0331
someone please help
pleaseeeee
@unknownunknown
Do we have the angle of the cannon, is it firing directly upward?
it dosent say @unknownunknown
Can you do a screenshot of the question?
i cant its a test
do you want me to put every detail? @unknownunknown
We will need every detail.. that's insufficient information as it is.
Help please A rock is launched from a cannon. It's height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.After one second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air. Find the height, in feet, of the rock after 5 seconds in the air.
@unknownunknown all of it
Alright well, I'm going to assume a lot, so I can't see if this will be definitely correct, but the question contains incorrect information to answer properly. So we'll just have to proceed with what we have.. Let me confirm the equation to make sure, one sec.
insufficient information*
so you cant solve it at all? @unknownunknown
@unknownunknown ?????
Is there a multiple choice or you must write the answer?
must write the answer @unknownunknown
So, if we let y equal the displacement, y = 9.8*t^2/2 + initial velocity * time So first of all, we'll need to solve for the initial velocity, can you rearrange the equation to solve for v? y=9.8*t^2/2 + v * t
Actually since it's coming down, we should make 9.8*t^2/2 negative. So y = -9.8*t^2/2 + v*t
i think its a large number for feet @unknownunknown
I'd say the answer is approximately 527, somewhere around there.
its not @unknownunknown
And how do you know that?
i just tried
@unknownunknown
Ok wait, let me work it out
Have you covered gravity in class? g = 9.8?
no @unknownunknown
Okay so. Let's say we have a function.. f(t) = -11*t^2 + 140*t If we plug into this equation t=1, we have -11 + 140 = 129 which satisfies the first part Then if we plug t=2, we have -11*4 + 140*2 = 236 which satisfies the second part
So then for f(5) = -11*25 + 140*5 = 425
right @unknownunknown
Okay, good.
can you help with another one @unknownunknown
Widget wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $23 to produce 2 widgets, $103 to produce 4 widgets, and $631 to produce 6 widgets.
@unknownunknown
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