Question

In a small company of 10 people the salaries are as follows:

5 people earn $25,000, 3 earn $27,000, 1 earns $34,000, and the owner earns $60,000

What is the mean and standard deviation (to the nearest dollar) of their salaries?

Mean salary:_______________ $a0

Standard Deviation: ______________$a1

Answer 1

Well for the mean you need to add count divide. Add 25,000 (5 times), 27,000 (3 times), 34,000, and 60,000. Count the number of people (10), and then divide the sum by that number.

Answer 2

what should i get

Answer 3

Well, what did you get?

Answer 4

hold up

Answer 5

im confused lol

Answer 6

Lol ok focus on the adding first. You should be adding 10 numbers. 25000+25000+25000+25000+25000+27000+27000+27000+34000+60000

Answer 7

300000

Answer 8

???????

Answer 9

Yep :) Then you need to divide by the number of people

Answer 10

divide it by 10

Answer 11

Yes

Answer 12

30000

Answer 13

the mean salary is 300000 and the standard deviation is 30000

Answer 14

???

Answer 15

Not quite. The 30,000 that you got is the mean.

Answer 16

well then now what

Answer 17

https://www.mathsisfun.com/data/standard-deviation-formulas.html

Now you have to subtract the mean from each number and square the result.

Answer 18

??????????

Answer 19

The first number (going back to the original problem) is 25,000. Subtract 30,000, and then take that difference and square it (multiply it by itself).