Physics
14 Online
OpenStudy (anonymous):
It takes 3.2 × 10^3 J of heat to melt an amount of gold (△Hf = 6.30 × 10^4 J/kg). How much gold do you have?
0.051 g , 0.51 g , 19 g , or 51 g ?
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OpenStudy (michele_laino):
please, for previous answer, I think inert gas, so not plasma
OpenStudy (michele_laino):
inert gas means a gas composed by neutral atoms
OpenStudy (anonymous):
ohh okay! so gas is the solution?
OpenStudy (michele_laino):
yes!
OpenStudy (anonymous):
ookay!! yay!! what about this one?
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OpenStudy (michele_laino):
here we have to compute this:
\[m = \frac{Q}{{\Delta {H_f}}}\]
where m is the mass of melted gold
OpenStudy (anonymous):
ok! what do we plug in? :/
OpenStudy (michele_laino):
hint:
\[m = \frac{Q}{{\Delta {H_f}}} = \frac{{3.2 \times {{10}^3}}}{{6.3 \times {{10}^4}}}\]
OpenStudy (anonymous):
okay! so we get 0.0507
so our solution is 0.051 g ?
OpenStudy (michele_laino):
no, it is 0.051 Kg
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OpenStudy (anonymous):
ohh and so converted to g that becomes 0.51 g? :/
OpenStudy (anonymous):
i forget the conversoins :/
OpenStudy (michele_laino):
no, it is 0.051*1000=...grams
OpenStudy (anonymous):
ohh right so our solution is 51 g ? :O
OpenStudy (michele_laino):
yes!
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OpenStudy (anonymous):
yay! thank you:)
OpenStudy (michele_laino):
:)