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OpenStudy (anonymous):
simplify the trigonometric expression?
sin^2(theta)/1- cos(theta)
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Nnesha (nnesha):
trig identity
sin^2 theta = what ?
OpenStudy (anonymous):
Just a suggestion, but go to mathway.com and it solves most problems your stuck on and helps break stuff down
OpenStudy (anonymous):
i know sin (theta) = 1/csc(theta)
Nnesha (nnesha):
just becareful sometimes it will give u the wrong answer
js :)
Nnesha (nnesha):
identity
\[\huge\rm sin^2 \theta + \cos^2 \theta = 1 \]
solve this for sin^2 theta
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OpenStudy (anonymous):
oh yeah, i forgot about that!
sin^2 (theta) = 1-cos^2(theta)
OpenStudy (anonymous):
Yeah you have to be exact with it and sometimes it wont give you the answer so, Yeah:) very helpful though still
Nnesha (nnesha):
yep right now apply difference of square method \[\huge\rm a^2 - b^2 = (a+b)(a-b)\]
OpenStudy (anonymous):
(1 + cos (theta))(1-cos(theta))?
OpenStudy (anonymous):
so the answer is 1 + cos(theta)?
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Nnesha (nnesha):
yep right \[\huge\rm \frac{ (1 - \cos \theta )(1+ \cos \theta)}{ 1-\cos \theta }\]
Nnesha (nnesha):
yes right
OpenStudy (anonymous):
cuz 1 - cos(theta) cancels out
OpenStudy (anonymous):
thanks!
Nnesha (nnesha):
np :-)
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