Question

A lead fishing weight with a mass of 57 g absorbs 146 cal of heat. If its initial temperature is 45∘C, what is its final temperature?

Answer 1

So far I have:\[146cal = 57g * C *(T _{f}-45)\]\[146\cal = 610.864J\]
so:\[610.864 = 57g * C * (T _{f}-45)\]
but where do i go from here? how do i find C and or Tf?

Answer 2

It is given in the problem that we are dealing with a lead weight. So, we need to use the heat capacity for lead in consistent units.