Question

Verify the identity.

cotx minus pi divided by two. = -tan x

Answer 1

\[\cot \left( x-\frac{ \pi }{ 2 } \right)=\frac{ \cos \left( x-\frac{ \pi }{ 2 } \right) }{ \sin \left( x-\frac{ \pi }{ 2 } \right) }\]
\[=\frac{ \cos x \cos \frac{ \pi }{ 2 }+\sin x \sin \frac{ \pi }{ 2 } }{ \sin x \cos \frac{ \pi }{ 2 }-\cos x \sin \frac{ \pi }{ 2 } }\]
\[\cos \frac{ \pi }{ 2 }=0,\sin \frac{ \pi }{ 2 }=1 \]

Answer 2

im not so sure i understand

Answer 3

\[=\frac{( \cos x)*(0)+(\sin x)*(1) }{ (\sin x)*(0)-(\cos x)*(1) }=\frac{ 0+\sin x }{ 0-\cos x }=-\tan x\]

Answer 4

ohhh okay thank you so much @surjithayer

Answer 5

yw