Question

Log5 12=log5 x

Answer 1

hint
\[\huge\rm log_b x = \log_b y\]
\[\huge\rm\cancel { log_b} x = \cancel{\log_b} y\]
x=y

Answer 2

wow... x = y.... that shortens the alphabet...

Answer 3

bases are same so you can cancels them

Answer 4

mhmmmm............ ?

Answer 5

let \[\log_{5} 12=y,\]
\[5^{y}=12,\log 5^y=\log 12,y \log 5=\log 12,y=\frac{ \log 12 }{ \log 5 }\]
\[\log_{5} x=y,5^y=x,\log 5^y=\log x,ylog 5=\log x,y=\frac{ \log x }{ \log 5 }\]
\[\frac{ \log x }{ \log 5 }=\frac{ \log12 }{ \log 5 }\]
log x=log 12
x=12