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OpenStudy (anonymous):
A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit?
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OpenStudy (michele_laino):
it is simple the toatl resistance is:
R=20+10=30 Ohm
so the requested current is:
I= V/R= 9/30=...Amperes
OpenStudy (michele_laino):
total*
OpenStudy (anonymous):
The answer choices are
0.38 A
0.75 A
1.35 A
6.00 A
So do I go with 0.38 A
OpenStudy (michele_laino):
sorry I have made an error
OpenStudy (michele_laino):
the total resistance is:
\[\Large R = \frac{1}{{\frac{1}{{10}} + \frac{1}{{20}}}} = ...Ohms\]
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OpenStudy (michele_laino):
what is R?
OpenStudy (michele_laino):
hint:
R=6.67 Ohms
so the requested current, is:
I=V/R= 9/6.67=...Amperes
OpenStudy (anonymous):
I got that answer but it doesn't match any answer choice.
OpenStudy (michele_laino):
what is your answer?
OpenStudy (anonymous):
oh I messed up I forgot to divide 9/6.67
I am so dumb the answer is 1.35A
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OpenStudy (michele_laino):
the answer is 1.35 Amperes, good job!
OpenStudy (anonymous):
Thank you for your help. I should have been able to do this on my own. I just missed a tiny detail when I was trying to solve it myself.
OpenStudy (michele_laino):
thanks! :)
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