Could somebody help me with a Stem & Leaf plot problem? I just suck at these.
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OpenStudy (anonymous):
OpenStudy (anonymous):
I think it's either B or D.
jimthompson5910 (jim_thompson5910):
jimthompson5910 (jim_thompson5910):
Are you able to find the median of this data set?
{0, 0, 5, 8
12, 13, 15, 18, 18, 19
22, 24, 26, 27, 27, 27
33, 35, 36
42, 44, 46
57}
OpenStudy (anonymous):
Are you suppose to ignore the zeros or not?
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
no do not ignore the 0s
jimthompson5910 (jim_thompson5910):
they are part of the data set
OpenStudy (anonymous):
Then the median is 26.
jimthompson5910 (jim_thompson5910):
close but no
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OpenStudy (anonymous):
Oh, 24. My bad. :)
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
what is the mode?
OpenStudy (anonymous):
27
jimthompson5910 (jim_thompson5910):
so "the median is greater than the mode" is false
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jimthompson5910 (jim_thompson5910):
what is the range of this data set?
OpenStudy (anonymous):
57
OpenStudy (anonymous):
so B is wrong.
jimthompson5910 (jim_thompson5910):
yep 57 is the correct range, not 52
jimthompson5910 (jim_thompson5910):
if you break up the data set into two halves, you'll find that the lower or left half is
0, 0, 5, 8, 12, 13, 15, 18, 18, 19, 22
what is the median of this data set shown above?
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OpenStudy (anonymous):
13
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
the median of the lower/left half of the data is exactly equal to the value of Q1
Q1 = first quartile
jimthompson5910 (jim_thompson5910):
so C is right. How about D?
OpenStudy (anonymous):
That's one of the things I'm having trouble with. I can't figure out which graphs are symmetrical and which aren't.
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jimthompson5910 (jim_thompson5910):
where is the median? what value is it?
OpenStudy (anonymous):
The median is in the middle and it's 24.
jimthompson5910 (jim_thompson5910):
well if this data set was perfectly symmetrical, then you would have a mirror like quality of the data values. The mirror itself would be at the median, aka the middle
jimthompson5910 (jim_thompson5910):
but notice how we have one lone outlier at 57
in contrast, we have a bunch of values clumped around the single digits (0, 0, 5, 8) and then a bunch more in the teens (12, 13, etc etc). So there are a lot more data values on the left side end, compared to the right end