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Iron-59 has a half-life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron? Show all calculations leading to a solution.
@tkhunny
25% is one half and then one half again.
25=100 e^(-.693 t/45.1) Ln(25)=ln(100) -.693 t/45.1 ln(25)-ln(100)=-.693 t/45.1 ln(25/100)=-.693t/45.1 t= - 45.1/.693 ( ln .25) t=90.2 days?
@ganeshie8 @Compassionate @Nnesha Is this right?
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100 ==> 50 in 45.1 days. 50 ==> 25 in 45.1 days.
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