Question

two point charges of +5.0 * 10^-5 C and -5.0 * 10^-5 C are separated by 0.50 m. Which of the following describes the force between them?

A. 90 N , attractive
B. 45 N, repulsive
C. 45 N , attractive
D. 90 N , repulsive

Answer 1

that force is attractive, since the charge have opposite sign

Answer 2

yes:) how can we find if it is 45 or 90?

Answer 3

furthermore, we have to apply the Coulomb law:
\[\Large F = K\frac{{{Q_1}{Q_2}}}{{{r^2}}} = 9 \times {10^9}\frac{{5 \times {{10}^{ - 5}} \times 5 \times {{10}^{ - 5}}}}{{{{\left( {0.5} \right)}^2}}}\]

Answer 4

so we get 90? so option A is our solutoin?

Answer 5

yes! correct!

Answer 6

yay!:)thanks!! okay onto the next! :P

Answer 7

:)