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Mathematics 21 Online
OpenStudy (anonymous):

log(base2)x^+x-52=2

OpenStudy (anonymous):

\[\log_{2}x ^{2}+x-52=2 \]

OpenStudy (anonymous):

|dw:1433299192056:dw|

OpenStudy (anonymous):

|dw:1433299285026:dw|

OpenStudy (anonymous):

Then I used the quadratic formula to get \[\frac{ -1\pm \sqrt{217} }{ 2}\]

OpenStudy (anonymous):

But my homework program has rejected all of my answers so I'm at a bit of a loss

sammixboo (sammixboo):

You were on the right track at \(\rm \color{purple}{x^2+x-52=4}\)

sammixboo (sammixboo):

Give me a minute

sammixboo (sammixboo):

Well, now you just want to solve it Oh, and do you know how many solutions you will have?

OpenStudy (anonymous):

I think that the problem is with the number in the square root.

OpenStudy (anonymous):

Not exactly, but there's at least one.

sammixboo (sammixboo):

Yes, there is 2 solutions for x

sammixboo (sammixboo):

Are they asking you to solve for x?

OpenStudy (anonymous):

Yes, I think I may have figured out the problem. For some reason my calculator was spitting out sqrt(217) but I think it should be Sqrt(225)

sammixboo (sammixboo):

Ok, so continue. Can you tell me what you got when you finish?

OpenStudy (anonymous):

x=7,-8

OpenStudy (anonymous):

Just checked it in my program and it's correct.

sammixboo (sammixboo):

Right :)

OpenStudy (anonymous):

I can't figure out for the life of me where my calculator came up with 217 instead of 225

sammixboo (sammixboo):

There is a few different ways you can solve \(\rm \color{purple}{x^2+x-52=4}\) One way is without square roots I was going to show you :)

sammixboo (sammixboo):

Hmm, are you using like a calculator on your computer or..?

OpenStudy (anonymous):

Yes, so I used a different one which is where I got the correct answer.

sammixboo (sammixboo):

Ah ok. You must've used 217 in the past, and it was suggesting this and that. Weird to explain. Clearing your history should work or just use a different calculator for now on :)

OpenStudy (anonymous):

Yeah, I definitely will. Thanks for your help, sometimes just talking it through helps as much as anything, getting over the block.

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