What is the area of the rectangle? Round to the nearest square inch.
A.
27 in2
B.
31 in2
C.
45 in2
D.
47 in2
http://static.k12.com/calms_media/media/1579000_1579500/1579373/2/4ac8cba629d8de89098f07b616577fd1aa6b2747/MS_IMC-150126-130912.jpg
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OpenStudy (igreen):
Use the Pythagorean Theorem to find the Length of the rectangle.
OpenStudy (igreen):
\(\sf a^2 + b^2 = c^2\)
'a' and 'b' are the two legs, in this case the length and the width, and 'c' is the hypotenuse, in this case the diagonal of the rectangle.
OpenStudy (anonymous):
so its \[5^2+b^2=8^2\] ??
OpenStudy (igreen):
Yep, you got it.
OpenStudy (igreen):
Now solve for 'b'
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OpenStudy (anonymous):
how do i solve for b again?
OpenStudy (igreen):
Then after you find 'b', multiply it to 5 to get the Area.
OpenStudy (igreen):
\(\sf 5^2 + b^2 = 8^2\)
Subtract 5^2 to both sides:
\(\sf b^2 = 8^2-5^2\)
Find the square root of both sides:
\(\sf b = \sqrt{8^2-5^2}\)
OpenStudy (igreen):
Simplify
OpenStudy (anonymous):
i got \[b=\sqrt{39}\]
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