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Mathematics 21 Online
OpenStudy (anonymous):

Need help please :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 @jakashaka123

OpenStudy (anonymous):

@deadpool117

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@texaschic101

OpenStudy (anonymous):

@Music_me

OpenStudy (anonymous):

@mathmath333

OpenStudy (anonymous):

@sweetburger

OpenStudy (anonymous):

idk this one -_-

OpenStudy (sweetburger):

So which of these do you need help with?

OpenStudy (anonymous):

OpenStudy (sweetburger):

so all 4 equations u need help with im assuming so lets start with the first

OpenStudy (anonymous):

yes and ok

OpenStudy (sweetburger):

Alright so 5x+7 = 5x+6 then you cancell out the 5x on each side and your left with 5=6 which is obviously not true so there are no solutions to this equation.

OpenStudy (anonymous):

1 ; b

OpenStudy (sweetburger):

for the next one you have -2x+3x= -3-2x this then simplifies to x=-1 which is one solution

OpenStudy (sweetburger):

this is one solution because the lines would interesect at only one point

OpenStudy (anonymous):

okay

OpenStudy (sweetburger):

For the next question you would multiply everything by 4 to get rid of the denominator and you would have x+3=3x+3 which would reduce to x=0 so one solution once again

OpenStudy (sweetburger):

Then for the last one x=-14 which is one solution

OpenStudy (sweetburger):

any other questions?

OpenStudy (anonymous):

so its 1: b 2 : a 3: a 4: a

OpenStudy (sweetburger):

ya no c's as that would require a final answer to come out of somethings along the line of 3=3

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