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OpenStudy (anonymous):
OpenStudy (anonymous):
@ganeshie8 @jakashaka123
OpenStudy (anonymous):
@deadpool117
OpenStudy (anonymous):
@iGreen
OpenStudy (anonymous):
@texaschic101
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OpenStudy (anonymous):
@Music_me
OpenStudy (anonymous):
@mathmath333
OpenStudy (anonymous):
@sweetburger
OpenStudy (anonymous):
idk this one -_-
OpenStudy (sweetburger):
So which of these do you need help with?
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OpenStudy (anonymous):
OpenStudy (sweetburger):
so all 4 equations u need help with im assuming so lets start with the first
OpenStudy (anonymous):
yes and ok
OpenStudy (sweetburger):
Alright so 5x+7 = 5x+6 then you cancell out the 5x on each side and your left with 5=6 which is obviously not true so there are no solutions to this equation.
OpenStudy (anonymous):
1 ; b
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OpenStudy (sweetburger):
for the next one you have -2x+3x= -3-2x this then simplifies to x=-1 which is one solution
OpenStudy (sweetburger):
this is one solution because the lines would interesect at only one point
OpenStudy (anonymous):
okay
OpenStudy (sweetburger):
For the next question you would multiply everything by 4 to get rid of the denominator and you would have x+3=3x+3 which would reduce to x=0 so one solution once again
OpenStudy (sweetburger):
Then for the last one x=-14 which is one solution
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OpenStudy (sweetburger):
any other questions?
OpenStudy (anonymous):
so its
1: b
2 : a
3: a
4: a
OpenStudy (sweetburger):
ya no c's as that would require a final answer to come out of somethings along the line of 3=3