Ask
your own question, for FREE!
Mathematics
16 Online
OpenStudy (amtran_bus):
Log differentiation?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amtran_bus):
But which one matches the one from wolfram?
OpenStudy (amtran_bus):
I really think it is a.
OpenStudy (xapproachesinfinity):
you are trying to differentiate
\[y=x^{\frac{2}{x}}\]
OpenStudy (amtran_bus):
yep
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
what did you do so far?
OpenStudy (amtran_bus):
typed in wolfram.
OpenStudy (xapproachesinfinity):
hehe i mean on your own
OpenStudy (xapproachesinfinity):
if you know already the answer from wolfram why are you still needing help
OpenStudy (amtran_bus):
The answer from wolfram dont match one of the choices I posted. Can you check for me
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
hmm interesting!
so wolfram given you an retriceanswer
OpenStudy (amtran_bus):
Its just in a different form.
OpenStudy (xapproachesinfinity):
well you could start with \[\Large y=e^{2\frac{\ln x}{x}}\]
OpenStudy (xapproachesinfinity):
that base change performed there
OpenStudy (xapproachesinfinity):
now you can differentiate it can you not?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
\[D(e^u)=\frac{du}{dx}e^u\]
OpenStudy (xapproachesinfinity):
chain rule
OpenStudy (xapproachesinfinity):
so it would be \[\Large y'=D(2\frac{\ln x}{x})e^{2\frac{\ln x}{x}}\]
OpenStudy (xapproachesinfinity):
D mean derivative
OpenStudy (xapproachesinfinity):
seems to me it will get to one of your answer choices
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!