http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%207.37.12%20PM_zpseia5o480.png.html I need help number 18 and 20 please check number 18 did P(A and B)=P(A) X P(B) P(A and B) / P(B)= P(A) = 0.15/0.6 = 1/4 ?
I would say \[ P(B|A)= \frac{P(A \cap B)}{P(A)} \] so \[ P(A)= \frac{P(A \cap B)}{P(B|A)} \] with P(B|A)= 0.6 and P(A \(\cap\) B) =0.15 from which you get P(A)= 0.25
ok,Thanks, can you do number 20?
For Q20 there are 20 marbles , 9 of them red. so 9/20 chance of choosing a red marble on the first pick. If you put the marble back in, then you will have 9/20 chance of picking red on the second pick, and 9/20 on the third. thus \[ \left(\frac{9}{20}\right)^3 \]
If you do not replace the marble, then the chance of picking a red marble on the first pick is 9/20, on the second 8/19 and on the third 7/18 thus \[ \left( \frac{9}{20}\right)\left( \frac{8}{19}\right)\left( \frac{7}{18}\right) \]
for part A, each time you pick is an independent event (because we put the marble back in the bag). That means each pick should be 9/20 and for multiple independent events, you multiply the individual probability to find the probability of all the events occurring.
thanks , can you have me some more ?
ok
this one I no idea
for event A, you count up the number of tiles that are consonants (the problem is y is sometimes a vowel e.g. fly, by, dry, or as a consonant e.g. you, yell, young, ...) not sure how to handle that.
and of course for B, first count the number of tiles that are vowels.
let me know if later you can solve , I need help if you can check my work it correct
can you check my answer ?
Let's assume y is only a consonant. then there are 42 vowels, 2 blanks, 56 consonants the chance of choosing a consonant on the first draw is 56/100 and the chance of choosing a vowel on the 2nd draw is 42/99
and we multiply (56/100)*(42/99)
http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%205.56.17%20PM_zpstctblc9x.png.html \[\frac{ 1 }{6 }\] \[\frac{ 1 }{ 6 } . of .60 = 10 ?\]
yes, and the 4 spot came up 10 times
ok, next http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%205.56.23%20PM_zpscjpwjnoy.png \[\frac{ 1 }{ 5 }\times30?\]
yes, so the black marble.
thanks,next http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%205.56.08%20PM_zpszlf9z9b0.png \[\frac{ 179 }{ 2237 }=0.0800\] 0.0800 x 100= 8% ?
I would leave the answer as 0.08
thanks http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%205.56.29%20PM_zpsfhmscrjx.png.html \[\frac{ 526 }{ 2392 }?\]
yes
http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%206.19.45%20PM_zpshyvuxfv0.png \[5<30 <80<90\]
your picture of the weather does not match up with 9/12000
let me check
for the weather question I think they want you to order A , B, C , D from least to most likely
ok, http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%206.20.56%20PM_zpsldqx0cs1.png \[\frac{ 9 }{ 12000 }?\]
9/1200 (not 12000) and expected number of defects is 9/1200 * 15000
\[\frac{ 9 }{ 1200 }\times1500?\]
yes
let go back to number 22 D<B<A<C ?
chance of rain on Fri is 5%, so chance of no rain is 95% i.e. D has prob= 95%
and they want the order smallest to biggest. D will be the biggest chance.
what numbers do you get for A, B , C and D ? for A and C, read off the number from the chart for B and D, do 100 - what is on the chart.
I get A 80, B 70, C 90, D 95
thanks you . Take me so long ti fix out , http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%207.35.09%20PM_zpse2zctvy9.png.html 3) Dependent 4) independent
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