Question

Solve (z + 6)2 = 5

A. {-6+√5,6-√5}

B. {-6±√5}

C. {√5±-6}

D. {6±√5}

Answer 1

is the 2 supposed to be a squared?

Answer 2

Yes

Answer 3

Okay. Thanks

Answer 4

Rule you can multiple exponents on both sides of an equation
so to solve for a:
a^2 = b
\[a^{2*(1/2)} = b^{1*(1/2)}\]
\[a^{1} = b^{1/2}\]
\[a = b^{1/2}\]

Answer 5

It might also help to remember BEDMAS order of operations.

Answer 6

\[\sqrt{(Z+6)^{2}}=\sqrt{5}\] Then solve for Z.

Answer 7

Would it be D?

Answer 8

I think you made a mistake in your algebra

Answer 9

No, because if you subtract 6 from both sides the square root of 5 is not what is subtracted you subtract the 6.