Question

11 Swimming pool water can be kept free of harmful bacteria by adding aqueous sodium chlorate(I),
NaOCl. This reacts with water to produce HOCl molecules which kill bacteria.
OCl–(aq) + H2O(reversible) OH–(aq) + HOCl (aq)
In bright sunshine, the OCl
– ion is broken down by ultra-violet lighT
OCL–(aq) + uv light → Cl–(aq)+ ½O2(g)
Which method would maintain the highest concentration of HOCl (aq)?
A acidify the pool water
B add a solution of chloride ions
C add a solution of hydroxide ions
D bubble air through the water

Answer 1

I get the part where uv light and ocl reaction is iroreversible so B and D cannot be the option

Answer 2

A?

Answer 3

Yeah but how?

Answer 4

As you said, B and D cannot be the answer, so it leaves C and A,
C cannot be correct as adding a solution.of hydroxide ions would faviur the reaction backwards and more reactants would be produced leaving A as the only option
Plus acidifying the solution means more H+ ions would be produce which would react to make more hocl
hocl

Answer 5

Hope this helps :)

Answer 6

Thankyou!!

Answer 7

And if this helped, please answer a question that i recently posted, if you know how to, badly need help in it :)