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Add the rational expressions:2x-1/(x+3)(x+2) + x-4/x+3
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@dan815
@Nnesha
@rational
^gO_Od one ^^^^^
sorry i dont normally tag people im in a hurry, last day of school for me :)
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it's okay i'm saying tag rational for rational expressions that was good ! :P alright first step find common denominator
oh ha ha!!
well x + 3 is common
\[\huge\rm \frac{ ? }{ (x+3)(x+2) }\] yes right (x+3) is common and (x+2) stay there|dw:1433451813766:dw| 2x-1 denominator and common denominator are the same so that's why 2x-1 stay same at the numerator now x-4 ave x+3 at the denominator but not x+2 so multiply (x-4) times (x+3)
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