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Mathematics 19 Online
OpenStudy (amtran_bus):

log question

OpenStudy (amtran_bus):

If I had ln(3x-10)=2

OpenStudy (amtran_bus):

I know you multiply each side by e

OpenStudy (amtran_bus):

But does it make the right side 2*e or e^2?

OpenStudy (anonymous):

You do not multiply both sides by e, you have to apply exponential on both sides

OpenStudy (anonymous):

Firstly multiply \(e\) both the sides..

OpenStudy (nottim):

NotMultiply.

OpenStudy (anonymous):

\(ln\) is basically called Natural Log, it is by default having base as \(e\)..

OpenStudy (nottim):

M4th got it.

OpenStudy (anonymous):

remember that \[e^{ln(x)} = x\]

OpenStudy (anonymous):

\[\ln = \color{green}{\ln _e}\]

OpenStudy (amtran_bus):

Yea, I know that. But the right side, the solution says you say e^2, and I would have said 2e.

OpenStudy (amtran_bus):

OpenStudy (anonymous):

Applying exponential on both side, you get: \[e^{ln(3x-10)} = e^{2}\]

OpenStudy (anonymous):

you are multiplying by "e" on the right side, that is wrong

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