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If I had ln(3x-10)=2
I know you multiply each side by e
But does it make the right side 2*e or e^2?
You do not multiply both sides by e, you have to apply exponential on both sides
Firstly multiply \(e\) both the sides..
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NotMultiply.
\(ln\) is basically called Natural Log, it is by default having base as \(e\)..
M4th got it.
remember that \[e^{ln(x)} = x\]
\[\ln = \color{green}{\ln _e}\]
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Yea, I know that. But the right side, the solution says you say e^2, and I would have said 2e.
Applying exponential on both side, you get: \[e^{ln(3x-10)} = e^{2}\]
you are multiplying by "e" on the right side, that is wrong
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