Amy has 35 tiles of the same shape and size in a box. The colors of and amounts of the tiles are shown below: 12 red tiles 8 yellow tiles 15 pink tiles Without looking in the box, Amy takes out a tile at random. She then replaces the tile and takes out another tile from the box. What is the probability that Amy takes out a yellow tile in both draws? 8 over 35 multiplied by 7 over 34 equal 56 over 1190 8 over 35 multiplied by 8 over 35 equal 64 over 1225 8 over 35 plus 7 over 34 equal 517 over 1190 8 over 35 plus 8 over 35 equal 560 over 1225
@Michele_Laino
@Michele_Laino
we have 8 favorable outcomes and 12+8+15= 35 possible outcomes so probability= favorable outcomes/ possible outcomes=...
that is the probability associated to a single extraction
favorable outcomes = 8 possible outcomes = 35 \[\Large \frac{{{\text{favorable outcomes}}}}{{{\text{possible outcomes}}}} = ...\]
so i have to divide
yes!
@Michele_Laino
the probability is 8/35 it is simple!
for a single extraction
so what about the other part
for second extraction, the probability is the same, namely it is 8/35, since Amy replaces the tile into the box. Now the requested probability is the product of the two probabilities, namely: probability = (8/35)*(8/35)=...?
64/1225
that's right!
Yay!
:)
A coin was flipped 150 times. The results of the experiment are shown in the following table: Heads Tails 90 60 Which of the following best describes the experimental probability of getting heads? It is 10% higher than the theoretical probability. It is 10% lower than the theoretical probability. It is equal to the theoretical probability for this data. The experimental probability cannot be concluded from the data in the table.
the theoretical probability is 1/2 since we have two possible outcomes, namely a head and a tail and we have one favorable outcome, namely a head, so probability = 1/2= 0.5 The experimental probability to get a head is 90/150=...
since we have 90 favorable cases and 150 possible cases or outcomes
0.6
SO IT 10% lower than the theoretical probability
now the difference between the experimental probability and the theoretical probability is: 0.6-0.5=...
so its 10% higher
that's right!
so the answer is A
yes!
yay!!!! last question sorry
ok!
The number of marbles of different colors stored in a hat is listed below: 8 red marbles 10 green marbles 6 blue marbles Without looking in the hat, Tessa takes out a marble at random. She replaces the marble and then takes out another marble from the hat. What is the probability that Tessa takes out a blue marble in both draws? fraction 1 over 16 fraction 1 over 12 fraction 1 over 4 fraction 1 over 2
here we have 8+10+6= 24 possible outcomes and we have 6 favorable outcomes so the probability associated to a single extraction is: p= 6/24 please simplify that fraction
0.25
we can divide both numerator and denominator by 6, wha do you get?
divide what?
oh 1/4
that's right!
so is that the answer @Michele_Laino
now, the probability associated to the second extraction is the same, namely 1/4. So the requested probability is given by the product between the above probabilities, namely p= (1/4)*(1/4)=...?
what is: \[\Large P = \frac{1}{4} \times \frac{1}{4} = ...?\]
Dang it
i just submitted my test
and i got it wrong
because i forgot to do the last part
):
but i got a 87% percent on my test
so have you passed it?
yes i did
CONGRATULATIONS!!!!!
im finished with math until next year yay!!!!!!!!
:)
Im going to be in 8th grade
ok!! :)
but Atleast i got a high B on my test !
and i have a A in Math!
good job!!
Thank you so much you really helped me undertand what i was doing. But i will be coming back just in case i need help lol!
ok! :)
hi marc just if u could, please only post 1x question per post cheers
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