x^2+4y=100 4y-x^2=-20 How in the world so I solve this system of equations please help fast! Do I use substitution? I don't clearly see how I would solve for x or y in either equation.
you can use substitution because x^2 on the first equation is positive and negative on the second equation. They will cancel out
*as i was, the 4y's will cancel out
so add them together
I get y=10
yup x^2-(-x^2)=2x^2 and then 100-(-20)=120 2x^2=120 120/2=60 x^2=60 and then take the square root
yeah so square root of 60 = x
exactly, and whatever x equals you plug it into to one of the equations to find y
I plugged it into the second equation and it worked. So does that mean there is only one solution?
no the number you plugged in is the answer for x. The answer you got after you plugged it in is y
remember, there is an x and a y so there has to be at least 2 answers, one for each letter
Yeah so (sqrt60, 10) is the only solution?
I got the answer wrong it was actually (6,4) :(((
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