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Chemistry 12 Online
OpenStudy (anonymous):

Will Fan and give medal. What is the correct balanced equation for the following equilibrium constant expression? [CO] superscript two times [O subscript two] over [CO subscript two] superscript two A) CO2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CO (g) + ½ O2 (g) B) CO2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CO (g) + O2 (g) C) 2 CO2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2 CO (g) + O2 (g) D) 2CO (g) + O2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CO2 (g)

OpenStudy (anonymous):

Is it B?

OpenStudy (anonymous):

@rosestella I have no clue....but if that's what you think it is....

OpenStudy (anonymous):

No wait

OpenStudy (anonymous):

[CO] superscript two times [O subscript two] over [CO subscript two] superscript two by this you mean [CO]^2[O2]/[CO2]^2

OpenStudy (anonymous):

So it should be C

OpenStudy (anonymous):

@rosestella Yeah. and thanks so much. I was so lost on that question.

OpenStudy (anonymous):

No problem you do know why those superscripts come up ? they're actually moles that have been made superscripts so considering them moles wee see that CO and CO2 have two moles while there's no superscript of oxygen this means that oxygen has one mole so C is the answer.

OpenStudy (anonymous):

Ohhh okay. That makes like 100x more sense.

OpenStudy (anonymous):

:))

OpenStudy (anonymous):

@rosestella Again thanks so much!

OpenStudy (anonymous):

*blushes* stop it you :p

OpenStudy (anonymous):

@divazozo101 was that answer correct?

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