write the equation of the function represented by the following graph medal
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
See if you can determine
* The amplitude
* The period
OpenStudy (anonymous):
3 and pi/4
jimthompson5910 (jim_thompson5910):
The period is actually pi/2
jimthompson5910 (jim_thompson5910):
But you have the right amplitude
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OpenStudy (anonymous):
got it then what next
jimthompson5910 (jim_thompson5910):
The y-intercept is not 0, and the relative extrema is at the y-intercept, so we have a cosine function here
Since the y-intercept is negative, this means that the cosine function has a negative coefficient
jimthompson5910 (jim_thompson5910):
General form
y = A*cos(Bx-C)+D
C = 0 and D = 0, so don't worry about those
|A| = amplitude
T = 2pi/B is the period
jimthompson5910 (jim_thompson5910):
with T = 2pi/B you can solve for B to get
B = 2pi/T
plug in the period T=pi/2 and simplify
OpenStudy (anonymous):
b=0 and t=0? @jim_thompson5910
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jimthompson5910 (jim_thompson5910):
T = pi/2 is the period
its not t = 0
jimthompson5910 (jim_thompson5910):
\[\Large B = \frac{2\pi}{T}\]
\[\Large B = \frac{2\pi}{\pi/2}\]
\[\Large B = ??\]