Question

which one of the following is a complex zero of P(x)=x^4-16

Answer 1

\[x^4-16=(x^2+4)(x^2-4)=(x^2+4)(x+2)(x-2)\]

Answer 2

the real zeros are \(2\) and \(-2\)

Answer 3

the complex ones you get from solving
\[x^2+4=0\] do you know how to do that?

Answer 4

wouldn't x=2?

Answer 5

no

Answer 6

\[x^2+4=0\\
x^2=-2\\
x=\pm\sqrt{-2}\] or
\[x=\pm\sqrt{2}i\]

Answer 7

it is not \(x=2\) because \(2^2+4=4+4=8\) not zero

Answer 8

okay so what if my choices are only..

Answer 9

i made a typo there
second line should be \(x^2=-4\)

Answer 10

\(-2i\) and \(2i\) are the zeros
pick \(-2i\)
who is jsara?

Answer 11

okay that makes sense.... and i just typed in random letters but I asked myself that same question as i was sending it hahahaha

Answer 12

if those letters are random i will have a beer now