Question

graph questions...

Answer 1

looks from my eyes that \(-3\) is one zero, crosses touches the x axis there

Answer 2

yeah i was thinking -3,-5,5

Answer 3

then look to see the other point where it crosses the x axis

Answer 4

no not \(-5\)

Answer 5

well then what would it be considering the choices

Answer 6

it does not cross the x axis at -5

Answer 7

do you have a choice that says \(-3\) and \(5\)?

Answer 8

you are only being asked where it touches or crosses the x axis

Answer 9

see attached image

Answer 10

the choices are on with the graph.. and theres a -3,-3,5

Answer 11

lol no you don't

Answer 12

go with NONE OF THESE

Answer 13

don't pick a wrong one just because it is there

Answer 14

thats reasonable hahaha okay heres the next one

Answer 15

name the zeros first

Answer 16

if you don't know them say so and i will help

Answer 17

-3,2,4??

Answer 18

yes

Answer 19

ok good now we can continue

Answer 20

you see how it touches at \(-3\) rather than crossing?

Answer 21

yes

Answer 22

that means one of the factors is \((x+3)^2\) rather than just \(x+3\)

Answer 23

then the answer would be B??

Answer 24

hold the phone we are not done

Answer 25

oh lol yeah sorry

Answer 26

by process of elimination that is the only one with \((x+3)^2\) in it

Answer 27

you should also have a \((x-2)^2\) as a factor, and \(x-4\) so yeah
\[(x+3)^2(x-2)^2(x-4)\]

Answer 28

okay that one was easy! heres the last graph one.. i think

Answer 29

looks like the zeros are at \(-3\) and also \(4\)

Answer 30

oh and at \(-1\)

Answer 31

yessss i got that :) so then

Answer 32

and it touches at \(4\) so it is going to look like this
\[a(x+3)(x+1)(x-4)^2\]

Answer 33

did you get that part?

Answer 34

yessss got that also

Answer 35

i hope it is clear
\(-3\) is a zero, so one factor is \(x+3\)
\(-1\) is a zero so one factor is \(x+1\) and
\(4\) is a zero, it touches at 4 so one factor is \(x-4\) ok good

Answer 36

now we need \(a\)

Answer 37

\((3,-6)\) is on the graph
that means if \(x=3\) you should get \(-6\) as a result

Answer 38

set \[a(3+3)(3+1)(3-4)^2=-6\] and solve for \(a\)

Answer 39

which is not has hard as it looks since \((3-4)^2=(-1)^2=1\) so you really only have
\[a\times 6\times 4=-6\]

Answer 40

-1/4??

Answer 41

i get
\[a=-\frac{1}{4}\] but it is late, check my algebra

Answer 42

oh look, C! it is always C
go with C

Answer 43

i suppose "ihatethis" is random letters as wel

Answer 44

you done or got more?

Answer 45

hahah okay ill go with C! thank you. ok now onto matrices..

Answer 46

oh god