So guys! I need some quick help and then I'm out! It's urgent and I can't resist not posting it here!
\[\frac{ 2 }{ 5 } (4x+6) = 2 (2-3x) + 6\]
My answer came out to something funky like 40x + 10 = 10 - 6x
Idk what I did wrong.
long time!
I know!!! Omg!! You're amazing!!
\[\frac{ 2 }{ 5 } (4x+6) = 2 (2-3x) + 6\] multiply \(5\) through out and get \[2 (4x+6) = 10 (2-3x) + 30\] distributing \[8x+12 = 20-30x + 30\]
Wait. So once I multiply I don't put it back as a fraction like: \[\frac{ 8 }{ 5 } x + \frac{ 12 }{ 5 }\]
we have \[\frac{ 2 }{ 5 } (4x+6) = 2 (2-3x) + 6\] multiplying \(5\) through out gives \[\color{red}{5}*\frac{ 2 }{ 5 } (4x+6) = \color{red}{5*}2 (2-3x) + \color{red}{5*}6\]
**Wait. So once I multiply I don't put it back as a fraction like:*** you could do that, by gan is showing a nicer way.. it gets rid of the fraction
the idea is multiply both sides by 5 (which is OK to do) and on the left, the 5/5 cancel. and no more fraction
btw, you should continue to simplify until you get x= some number.
Yes, that's what I was doing. I got 1! Thanks guys for the help! I appreciate it! I'll use this as an example to lead me through more! Thanks again!
I wish you were my teacher, ganeshie! It's soo much easier with your steps!!
one key thing about math in general is - follow the rules and all your methods will produce the same answer in the end and ofcourse there always exists the best way to do any problem :)
Yes, that's what I was doing. I was taught some other way like finding LCD which drives me insane!!! I always want to die when I see finding LCD. It's a killer! Oh yes! That's why I always ask you, because you always have some way that I do not know!!;))
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