Question

anyone who can answer this?
a point moves on the parabola y^2=8 in such a way that the rate of change of the ordinate is always 5 units/second. how fast is the abscissa changing when the ordinate is 4?

Answer 1

ordinate : y coordinate
abscissa : x coordinate

Answer 2

could you double check the equation of parabola, is it really `y^2=8` ?

Answer 3

yes it is y^2=8

Answer 4

i also think that the questions seems lacking, or something wrong?

Answer 5

im pretty sure the equation is y^2=8\(\color{red}{x}\)

Answer 6

y^2 = 8 does not produce a parabola when you graph

Answer 7

yes..

Answer 8

i also think that way..

Answer 9

good, lets make it y^2=8x

Answer 10

we're given
\(\dfrac{dy}{dt}=5\)

Answer 11

\[y^2=8x\]
differentiate both sides with respect to \(t\)

Answer 12

\[2y \frac{ dy }{ dt} = 8\frac{ dx }{ dt }\]

Answer 13

is that right?

Answer 14

Yes, plugin the given values

Answer 15

i got it

Answer 16

\[\frac{ dx }{ dt} = 5\]

Answer 17

thanks sir

Answer 18

Yw!