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Mathematics 17 Online
imqwerty (imqwerty):

fun question

OpenStudy (anonymous):

ask away

imqwerty (imqwerty):

OpenStudy (anonymous):

0.0 thats alot of lines

OpenStudy (anonymous):

b

imqwerty (imqwerty):

no

OpenStudy (anonymous):

then it has to be c

OpenStudy (anonymous):

there no other way at all

OpenStudy (anonymous):

too much work.... :-/ looks challenging, maybe later....

imqwerty (imqwerty):

no

OpenStudy (yadu123):

how is this fun

OpenStudy (anonymous):

i do not know

OpenStudy (anonymous):

what level math is this?

OpenStudy (anonymous):

9 +10 = 21

OpenStudy (anonymous):

ha xD

imqwerty (imqwerty):

10-11th grade

Parth (parthkohli):

This question is just so bad that coordinate geometry seems to be the way to go.

OpenStudy (anonymous):

wait you guys still have school

OpenStudy (anonymous):

i would probably say d. because it seems like the 2 triangles are similar. so if you divided the larger one by the area of the smaller one you would get 2 because the larger one is double the smaller one.

OpenStudy (anonymous):

man down in Florida it's over

Parth (parthkohli):

I was looking at the wrong triangles. Oops. Yes, they do look like they're similar.

imqwerty (imqwerty):

i'll be posting the solution after i eat 2hot dogs

OpenStudy (anonymous):

XD

OpenStudy (anonymous):

@Jennjuniper that is a clever observation!

OpenStudy (anonymous):

it was all wrong!! it should be \[RS=PS=1\] and \[AQ=AP=\sqrt{2}\]

imqwerty (imqwerty):

shall i tell the solution now??

OpenStudy (mathstudent55):

Ratio is 2/1

imqwerty (imqwerty):

ok i'll wait

imqwerty (imqwerty):

thats right @mathstudent55

OpenStudy (mathstudent55):

Areas are 0.5 & 0.25

OpenStudy (mathstudent55):

Great q. Thanks.

OpenStudy (badhi):

\[\measuredangle RAS =60 ^\circ \] and since RA = AS, \(\Delta RAS\) is a equilateral triangle Therefore \[\measuredangle RSP = 30^\circ\] , \(\Delta RSP\) is a isosceles triangle Guess that information is enough for finding the area of the RSP. \(AP = AQ = \sqrt{2}\) (considering AFP and ABQ) \(\measuredangle PAQ = 30^\circ\) since \(\measuredangle FAP = \measuredangle QAB = 45^\circ\) Guess that is enough to find the area of the APQ

imqwerty (imqwerty):

yes u've told the right areas too @mathstudent55

imqwerty (imqwerty):

well done @BAdhi

OpenStudy (anonymous):

great answers both! @mathstudent55 and @BAdhi !!

OpenStudy (badhi):

Thanks for posting a good question ;)

imqwerty (imqwerty):

i'll keep posting such questions everyday @BAdhi

imqwerty (imqwerty):

solution

ganeshie8 (ganeshie8):

Nice!

ILovePuppiesLol (ilovepuppieslol):

i like fun questions !!!!!!

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