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Mathematics 18 Online
OpenStudy (anonymous):

so three cards are drawn from a deck of 52 cards. what are the ODDS that all three cards are spades? how do you do odds? opposed to probability?

OpenStudy (anonymous):

i know that it's the ratio successes :failures so i tried 13 C3 : 39C3 but it didnt get me the right answer

OpenStudy (cwrw238):

the probability that all 3 cards are spades is the product of the individual probabilities

OpenStudy (cwrw238):

there are 13 spades in a pack of 52 so P(3 spades) = 1/4 * 12/51 * 11/50

OpenStudy (anonymous):

how about the odds?

OpenStudy (cwrw238):

this equals 11/850 as a fraction

OpenStudy (cwrw238):

not sure about the odds I guess its 839 to 11 against it happening (839 because its 850 - 11)

OpenStudy (anonymous):

that's right 11:830

OpenStudy (anonymous):

11:839*

OpenStudy (anonymous):

but im a bit confused on how to get it

OpenStudy (cwrw238):

what part are you confused about?

OpenStudy (anonymous):

finding the odds of something

OpenStudy (cwrw238):

I dont back horses so I'm not much help there lol

OpenStudy (cwrw238):

when you said right 11:839 - was that the answer given in the book or on-line?

OpenStudy (anonymous):

answer key from my teacher

OpenStudy (cwrw238):

right well if my memory serves me right there are 2 kins of odds odds on and odds against so ithink 11:839 is the odds ON 3 spades being drawn ad 839:11 is the odds AGAINST 3 spades being drawn

OpenStudy (cwrw238):

a simple example would be if a horse has the probability of winning a race the odds ON will be 1:3 and odds against will be 3:1 - the 2 numbers must add up to 4

OpenStudy (cwrw238):

* has the probability 1/4 of winning a race

OpenStudy (anonymous):

but for cards, you have to draw 3 cards? so wont that change

OpenStudy (cwrw238):

no the rule is still the same you first work out the probabiility as a fraction and work out the odds on by subtraction ( in our case 850-11) your teacher wanted the odds ON drawing 3 spades.

OpenStudy (anonymous):

i tried that for another problem. which is now 5 cards are draw... odds of get 5 face cards.

OpenStudy (anonymous):

so if i treat it like probability it would be 792/2598960

OpenStudy (cwrw238):

some fraction i have a graphical calculator so i can get that in its most simple form - its 33/ 108290 - so can you work out the odds from this result?

OpenStudy (anonymous):

how did you get that?

OpenStudy (cwrw238):

as i said my calculator does the addition of fractions

OpenStudy (anonymous):

i mean like the probability in general?

OpenStudy (cwrw238):

you could do it manually by finding prime factors but its a bit tedious

OpenStudy (anonymous):

how do you know what fractions to add though

OpenStudy (cwrw238):

well how did you get your fraction 792/2598960?

OpenStudy (anonymous):

the number of successes is 12C5 over total number of outcomes is 52C5

OpenStudy (cwrw238):

oh ok thats another way of doing it the other way is 12/52 * 11/51 * 10/50 *9/49 * 8/48

OpenStudy (cwrw238):

- beceuse theres 12 face cards out of 52 - then we have 11 left out of 51 etc they are independent evants so the probabilities are multipl;ied

OpenStudy (anonymous):

hm, i get a different answer

OpenStudy (cwrw238):

you can simplify some of the fractions first so its same as 3/13 * 11/51 * 1/5 * 9/49 * 1/6

OpenStudy (anonymous):

oh i got the answer. thank you xD

OpenStudy (cwrw238):

yw

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