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If AR = 12 m and RE = 4 m, what is the ratio of the areas of ARH and AES? 3 : 4 4 : 9 9 : 16 9 : 1
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The ratio of linear measurements squared will find you the ratio of area measurements, but first you must simplify:\[\frac{ 12 }{ 4 }=\frac{ 3 }{ 1 }\] Then you square\[\frac{ 3^{2} }{ 1^{^{2}} }\]
Took me a while to get the symbols right this time :)
4:9? @danielgarcia413
Close, 9:1
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@danielgarcia413 Thanks, im kind of starting to get this stuff!
No problem, good to hear!
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