Question

If you have a 45.0 V battery connected to a 10.0 Ω resistor and a 5.00 Ω resistor in series, what will be the total power output in the circuit?

A. 45.0 W

B. 135 W

C. 203 W

D. 405 W

Answer 1

total resistance is:
R= 10+ 5=...

Answer 2

15!

Answer 3

ok!
so current is:
I=45/15=...

Answer 4

3!

Answer 5

ok!
Then the dissipated power is:
W= I* V= 3*45=...watts

Answer 6

135!so our solution is choice B? :O

Answer 7

yes! since it is the outputted power

Answer 8

ooh okie! thank you!!:)

Answer 9

:)