Question

Please reply...toms my paper...
Given CO(g) + 2
1 O2(g) → CO2(g) ∆Ho
= –283 kJmol–1
H2(g) + 2
1 O2(g) → H2O(l) ∆Ho
= –286 kJmol–1
H2O(g) → H2O(l) ∆Ho
= –44 kJmol–1
what is the change in enthalpy, ∆Ho
, for the following reaction?
CO2(g) + H2(g) → CO(g) + H2O(g)
A –525 kJmol–1 B –41 kJ mol–1 C +41 kJ mol–1 D +525 kJmol–1