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OpenStudy (anonymous):
Please reply...toms my paper... Given CO(g) + 2 1 O2(g) → CO2(g) ∆Ho = –283 kJmol–1 H2(g) + 2 1 O2(g) → H2O(l) ∆Ho = –286 kJmol–1 H2O(g) → H2O(l) ∆Ho = –44 kJmol–1 what is the change in enthalpy, ∆Ho , for the following reaction? CO2(g) + H2(g) → CO(g) + H2O(g) A –525 kJmol–1 B –41 kJ mol–1 C +41 kJ mol–1 D +525 kJmol–1
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