this can be a very good post...
the best post ever!
yes, it can, but it isn't
Seriously though, what's the question it shows it's in calculus 1 so it had me excited :P
\(\Large \displaystyle\sum_{n=k}^{\infty}~f(n)=~?\) (starting from any whole number k) we know: \(\Large \displaystyle\sum_{n=1}^{\infty}A_n=\frac{A_1}{1-r}\) what is r in initial case? \(\Large \displaystyle r=\lim_{n\rightarrow \infty}\frac{a_{n+1}}{a_n}\) so, \(\Large \displaystyle\sum_{n=k}^{\infty}~f(n)~=~\frac{A_k}{1-r}\) \(\Large \displaystyle\sum_{n=k}^{\infty}~f(n)~=\frac{A_k}{\displaystyle1-\left(\lim_{n\rightarrow \infty}\frac{a_{n+1}}{a_n}\right)}\) i don't even know why so many people are viewing.... (btw, just had to depart for a little)
that is just a general thing that works for any f
just a quick thought ... ))
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