Question

Historical Feature
3HK=-p and H^3+K^3=-q
solve for K in 3HK=-p and substitute into H^3+K^3=-q. Then show that
H=3 sqrt -q/2+sqrtq^2/4+p^3/27

Answer 1

Well it says to solve 3HK=-p for K
then substitute that into H^3+K^3=-q
have you done this part and if so can you show how far you have gotten with it?

Answer 2

no

Answer 3

ok well if you do that you should end up with a quadratic in terms of H^3