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One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit? A. 3.0 A B. 1.5 A C. 0.75 A D. 0.33 A
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|dw:1433875036891:dw|
equilvalent resistance is 30?
no, it is: \[\Large {R_{EQ}} = 10 + \frac{1}{{\frac{1}{{10}} + \frac{1}{{10}}}} = ...\Omega \]
oh oops ! so it is 5!
are you sure?
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oh oops i did not see the 10 in front! so it is 15!
correct!
now, the requested current is: I=45/15=...amperes
3! so our solution is choice A? :O
that's right!
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yay! thank you!!:D
:)
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