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OpenStudy (anonymous):
If you have a 45.0 V battery connected to a 10.0 ohms resistor and a 50.0 ohms resistor in series, what will be the total power in the circuit? A. 50.0 W B. 33.8 W C. 203 W D. 405 W
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OpenStudy (michele_laino):
current is: I=V(R_1+R_2)= 45/(50+10)=...? since resistors #1 and #2 are connected in series
OpenStudy (anonymous):
45/60 = 0.75?
OpenStudy (michele_laino):
ok!
OpenStudy (michele_laino):
now, the requested power is: P=45*0.75=...watts
OpenStudy (michele_laino):
namely: power P= V*I
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OpenStudy (anonymous):
33.75! so our solution is choice B? 33.8 W ?
OpenStudy (michele_laino):
correct!
OpenStudy (anonymous):
yay! thanks!!:)
OpenStudy (michele_laino):
:)
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