Question

Solve x^3 = 64 over 27

Answer 1

@LegendarySadist

Answer 2

@Nnesha

Answer 3

\[x^3=\frac{ 64 }{ 27 },27x^3-64=0\]
\[\left( 3x \right)^3-3^3=0\]
\[a^3-b^3=\left( a-b \right)\left( a^2+ab+b^2 \right)\]

Answer 4

So is it. C

Answer 5

i don;t see options.

Answer 6

Solve x3 = 64 over 27.

±8 over 3
8 over 3
±4 over 3
4 over 3

Answer 7

correction \[\left( 3x \right)^3-4^3=0\]only real value is
3x-4=0
\[x=\frac{ 4 }{ 3 }\]

Answer 8

So its D right

Answer 9

\(64 = ?^3\)

Answer 10

\(27=??^3\)

Answer 11

\(x^3 =\dfrac{64}{27}=\dfrac{?^3}{??^3}=(\dfrac{?}{??})^3\)
hence \(x= \dfrac{?}{??}\)
your duty is find out what are ? and ??

Answer 12

@Loser66. D

Answer 13

So its D right @Nnesha