Gaseous C2H4 reacts with O2 according to the following equation:
C2H4 (g) + 302 - 2CO2 + H2O (g)
What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?
A) 17.3 L
B) 42.9 L
C) 3.86 x 10^2 L
D) 1.29 x 10^2 L
E) Not enough information is given to solve the problem.

Question

Gaseous C2H4 reacts with O2 according to the following equation:
C2H4 (g) + 302 -> 2CO2 + H2O (g)
What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?
A) 17.3 L
B) 42.9 L
C) 3.86 x 10^2 L
D) 1.29 x 10^2 L
E) Not enough information is given to solve the problem.

cuanchi · Answer

1) The reaction is not well balanced. It produce 2H2O. Anyway will not affect your calculations in this problem.
2) according to the stoicheometry for each mole of C2H4 you need 3 moles of O2, then, for 
5.75 mol C2H4 you will need 3 times more, 5.75 x 3= 17.25 moles of O2.
3) one mole of any gas at STP conditions will occupy 22.4 L. Do the math! I guess will be C or D that you forgot to put the values

hpfan101 · Answer

Ok, thank you! 
Oh, I didn't realize I forgot to put in the values for C & D. My bad.