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Mathematics 25 Online
OpenStudy (anonymous):

Does... 1. sin(2pi + Ѳ) = -cos Ѳ 2. cos(2pi - Ѳ) = cos Ѳ I don't know what to do with the pi's. My teacher never taught me how to check if equations are identities with pi in them. Please explain.

OpenStudy (johnweldon1993):

|dw:1433989500490:dw|

OpenStudy (johnweldon1993):

The unit circle Let me ask...if you start |dw:1433989606182:dw| And you travel 2π around the circle...where will you end up?

OpenStudy (anonymous):

it would be in the same place

OpenStudy (johnweldon1993):

Right...you would end up in the same exact place, meaning we can just ignore them and just worry about 1) \(\large sin(\theta) = -cos(\theta)\) and clearly that is NOT a correct statement Does that make sense?

OpenStudy (anonymous):

okay but what about if it wasn't 2pi? what would you do if it was something where you couldn't ignore it?

OpenStudy (johnweldon1993):

It would be the same for 2) as well \(\large cos(2\pi - \theta) = cos(\theta)\) since 2π brings us back to the same place, we ignore it and just have \[\large cos(-\theta) = cos(\theta)\] which *since we know cos is an odd function is correct

OpenStudy (anonymous):

what do you mean an odd function?

OpenStudy (freckles):

cos is an even function sin is an odd function

OpenStudy (johnweldon1993):

Oops, yup my mistake there!

OpenStudy (anonymous):

okay how does that help?

OpenStudy (johnweldon1993):

It is an identity \[\large cos(-\theta) = cos(\theta)\]

OpenStudy (anonymous):

You said since cos in an odd function it is correct? what do you mean by that? How would it being an odd function help

OpenStudy (anonymous):

i meant it being an even function

OpenStudy (johnweldon1993):

Yeah I did too, still sorry about that typo lol So here maybe a visual would help with this...the graph of cos(x) is |dw:1433991380473:dw|

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