Does... 1. sin(2pi + Ѳ) = -cos Ѳ 2. cos(2pi - Ѳ) = cos Ѳ I don't know what to do with the pi's. My teacher never taught me how to check if equations are identities with pi in them. Please explain.
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The unit circle Let me ask...if you start |dw:1433989606182:dw| And you travel 2π around the circle...where will you end up?
it would be in the same place
Right...you would end up in the same exact place, meaning we can just ignore them and just worry about 1) \(\large sin(\theta) = -cos(\theta)\) and clearly that is NOT a correct statement Does that make sense?
okay but what about if it wasn't 2pi? what would you do if it was something where you couldn't ignore it?
It would be the same for 2) as well \(\large cos(2\pi - \theta) = cos(\theta)\) since 2π brings us back to the same place, we ignore it and just have \[\large cos(-\theta) = cos(\theta)\] which *since we know cos is an odd function is correct
what do you mean an odd function?
cos is an even function sin is an odd function
Oops, yup my mistake there!
okay how does that help?
It is an identity \[\large cos(-\theta) = cos(\theta)\]
You said since cos in an odd function it is correct? what do you mean by that? How would it being an odd function help
i meant it being an even function
Yeah I did too, still sorry about that typo lol So here maybe a visual would help with this...the graph of cos(x) is |dw:1433991380473:dw|
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