HELLLLP ME PLEASE!!!!!! if a line with a slope of 4 crosses the y-axis at (0,1), what is the equation of the line?
Well when we write out the equation of the line, we look for 2 things. The slope and the y-intercept. The y-intercept is what the y value will be when x is 0. Are you with me so far?
Yes I guess
So we are going to write it out in the form \[\large y=mx+b\] with m as the slope and b as the y-intercept. What do you think it would look like in this form?
y=m*0+b
Well m is the slope. So it HAS to be 4, right?
ok so slope is 4 but im still confused
Here, let's take out the b for a second. \[\large y=4x\] So what happens when you plug in 0 for x?
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The choices are y-4x=1 y+4x=1 x-4y=1 x+4y=1
so is it y+4X=1
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@LegendarySadist can you help me out some more
Yes, sorry for the delay. So if we have \[\large y=4x\] what will we get if we plug in 0 for x?
you get babies
just x right because 4*0=0
Yes so \[\large y=4*0\\\large y=0\] So when x is 0, y is 1. That means our y-intercept is 1. So now that we know that, how would we write the equation?
y-4x=1
Yes, that would be it. Good job :)
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