Mathematics
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OpenStudy (anonymous):
FAN AND MEDAL
Choose the point-slope form of the equation below that represents the line that passes through the point (−1, 6) and has a slope of −3
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pooja195 (pooja195):
\[\huge~y-y_1=m(x-x_1)\]
pooja195 (pooja195):
m=slope
(x1,y1)
OpenStudy (theraggedydoctor):
Btw.. It's *Stephen
OpenStudy (anonymous):
still confused
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pooja195 (pooja195):
@kyle55 what part are you confused about?
OpenStudy (anonymous):
So since i have the slope of -3 and the one point
what do i do first
pooja195 (pooja195):
\[y-y1=-3(x-x1)\]
OpenStudy (anonymous):
so that would be
y- 6 = -3(x + 1) ?
pooja195 (pooja195):
yep :)
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OpenStudy (anonymous):
Then from there distribute?
OpenStudy (anonymous):
no
pooja195 (pooja195):
Well it said the point slope form
pooja195 (pooja195):
So i dont think so :/
OpenStudy (anonymous):
oh so thats it
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pooja195 (pooja195):
yes :)
OpenStudy (anonymous):
tyvm
OpenStudy (anonymous):
can u check my next question?
pooja195 (pooja195):
sure :)
OpenStudy (anonymous):
Choose the point-slope form of the equation below that represents the line that passes through the points (−3, 2) and (2, 1).
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OpenStudy (anonymous):
what do i do first? same equation?
pooja195 (pooja195):
First we need to find the slope do you know how?
OpenStudy (anonymous):
y1-y2 over x1-x2
pooja195 (pooja195):
Yes so find the slope first :)
OpenStudy (anonymous):
1 over -1?
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OpenStudy (anonymous):
or -1
pooja195 (pooja195):
yes
pooja195 (pooja195):
Now we plug it into the same equation
lets use the point (-3,2)
and the slope as -1
OpenStudy (anonymous):
so y - 2 = -1(x + 3
pooja195 (pooja195):
yep
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OpenStudy (anonymous):
a. y + 3 = −5(x − 2)
b. y − 2 = −5(x + 3)
c. y + 3 = −one fifth(x − 2)
d. y − 2 = −one fifth(x + 3)
OpenStudy (anonymous):
those were the answers
pooja195 (pooja195):
ooo our slope must be wrong :/ let me double check
pooja195 (pooja195):
it would be -1/5
OpenStudy (anonymous):
so d
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pooja195 (pooja195):
yep :)
The rest of the equation remains the same
OpenStudy (anonymous):
got more time?
pooja195 (pooja195):
I can help with more but repost it :)
pooja195 (pooja195):
On a diffrent thread :P
OpenStudy (anonymous):
ill post my last 2 questions
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pooja195 (pooja195):
ok :)