FAN AND MEDAL!!! Solve for x. -ax + 2b 8 A) x the quantity negative 2 times b plus 8 all over negative a C) x the quantity negative 2 times b minus 8 all over a

Question

FAN AND MEDAL!!! Solve for x. -ax + 2b > 8 A) x < the quantity negative 2 times b plus 8 all over negative a B) x > the quantity negative 2 times b plus 8 all over negative a C) x < the quantity 2 times b minus 8 all over negative a D) x > the quantity negative 2 times b minus 8 all over a

rhystic · Answer

treat the > as an = and solve for x first then put the > back in.

anonymous · Answer

but there are 2 variables

rhystic · Answer

it doesn't matter as you are only solving for x. You treat the other variable b as a constant.

anonymous · Answer

So it's A?

rhystic · Answer

how did you arrive to that answer?

anonymous · Answer

-ax + 2b > 8 Subtract 2b from both sides -ax > 8 - 2b Divide both sides by -a and switch the > sign to < x < 8 - 2b all over -a

anonymous · Answer

So it's A?

rhystic · Answer

why would you switch the signs?

anonymous · Answer

You have to switch the sign when you divide by a negative

anonymous · Answer

So it's A, right?

rhystic · Answer

yep