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Chemistry 16 Online
OpenStudy (hpfan101):

Consider the following reaction: CH4 (g) + 4CL2 (g) -> CCl4 (g) + 4HCL (g) What mass of CCl4 will be formed if 1.20 moles of methane react with 1.11 moles of chlorine? A) 185 g B) 171 g C) 683 g D) 42.7 g E) 19.7 g

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