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ABC has side lengths 20,24, and 31. Do the side lengths form a Pythagorean triple?
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Does A^2 + B^2 = C^2?
yes
\( 20^2 * 24^2= 31^2 ? \)
here \(C>B,A\)
Then t forms a triple
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So 20 * 20 =400 and 24*24= 576
But A^2 + B^2 does not equal C^2
it should be this \(20^2 \color{red}{+} 24^2= 31^2 ?\)
\(576+400= 976\)
the answer choices are yes or no
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Oops didnt see that thanks @mathmath333
Ok so \(A^2+B^2 = 976 \) does C^2 = 976 ? If not then it is no.
So does \(31*31=976\) ?
@billyjean ?
yes it equals to 976
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No no no it does not lets multiply it again and see what it turns out to be.
|dw:1434048037034:dw|
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