Question

Trig: How does this equal one?

\( tan^2 \theta - sec^2 \theta = 1 \)

Answer 1

I have

\( tan^2 \theta - sec^2 \theta = 1 \)
\( \frac{sin^2 \theta}{cos^2 \theta} - \frac{1}{cos^2 \theta} \)

I am stuck here

Answer 2

I think I got it

Answer 3

It shouldn't

Answer 4

Let me know if this is correct




\( tan^2 \theta - sec^2 \theta = 1 \)
\( \frac{sin^2 \theta}{cos^2 \theta} - \frac{1}{cos^2 \theta} \)
\( \frac{1+cos^2 \theta}{cos^2 \theta} - \frac{1}{cos^2 \theta} \)
\( \frac{cos^2 \theta}{cos^2 \theta} = 1 \)

Answer 5

do you mean -1?
recall
\[\sin^2(\theta)+\cos^2(\theta)=1 \]
divide both sides by cos^2(theta)
(this equation comes )