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Mathematics 14 Online
OpenStudy (anonymous):

I don't even know where to start, please help

OpenStudy (anonymous):

is the center \((4,-3)\)?

OpenStudy (anonymous):

from what I can see, yes

OpenStudy (anonymous):

then one thing for sure, it will look like \[(x-4)^2+(y+3)^2=r^2\] your final job is to find \(r^2\)

OpenStudy (anonymous):

so is that the equation for 1a ?

OpenStudy (anonymous):

can someone else help me, I'm completely lost

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