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Mathematics 19 Online
OpenStudy (dominantvampire):

kindly help please. A Block Of Mass 12 kg

OpenStudy (dominantvampire):

a block of mass 12 kg is released from rest om a friction-less incline of the angle theta=30 below the block is a spring having spring constant 10^4 N/m. the block stops momentarily when it compresses the spring by 4 cm. how far does the block move down the incline from its rest position to this stopping point

OpenStudy (dominantvampire):

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OpenStudy (dominantvampire):

no body knows perhaps, sighs.

OpenStudy (anonymous):

do you know how to use energy conservation??

OpenStudy (dominantvampire):

yes.

OpenStudy (dominantvampire):

Ki+Ui=Kf+Uf ?

OpenStudy (anonymous):

yep... initial energy will be the potential energy of the block and the final energy will be the spring extension.. can you relate?

OpenStudy (anonymous):

compression**

OpenStudy (dominantvampire):

the Ki is 0 and Uf would be zero as well i guess

OpenStudy (anonymous):

Uf would not be zero as the spring is compressed and is having potential energy its like the GPE is getting converted to spring energy

OpenStudy (anonymous):

GPE is gravitational potential energy

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