Question

What is the rate of change for f(x) = –2 cos 4x – 3 on the interval from x = 0 to x = pi/4

Answer 1

Answer choices
A. 2/pi
B.pi/2
C.16/pi
D. pi/16

Answer 2

@ganeshie8

Answer 3

okay so plug in values for both 0 and π/4

Answer 4

and then use (f(0)-f(π/4))/(0-4)

Answer 5

don't forget to medal... any questions just message me

Answer 6

Hey sorry my computer had to be restarted. How do I give you a medal?

Answer 7

you just click best answer, and it medals

Answer 8

@cramos725 could you help me a bit more?

Answer 9

sure

Answer 10

what do u need help on?

Answer 11

I am new to this type of problem entirely so could you show me the plugging in part?

Answer 12

okay sure... so f(x) = –2 cos 4x – 3
when you plug in 0, you have -2 cos(4(0)) -3
which is equal to -2 cos(0) -3
= -2(1)-3
=-2-3
=-5

Answer 13

oh ok I see what I did wrong

Answer 14

when you plug in π/4, you get -2(cos4(π/4))-3
so you get -2 cos(π) -3
=-2(-1)-3
=-1

Answer 15

glad i could help

Answer 16

and the denominator should be (0-π/4)

Answer 17

i made a mistake typing it in earlier

Answer 18

you get -5-(-1) which is -4
all over 0-π/4

-4/(-π/4)
which is 16/π

Answer 19

oh i see. Thank you so much I really appreciate yout time.